ZipHandle = zipfile.ZipFile('test.zip', 'w') # add whole "dir" to "test.zip" (when you open "test.zip" you will see only "dir") #!/usr/bin/env pythonĭef addDirToZip(zipHandle, path, basePath=""):Īdding directory given by \a path to opened zip file \a basePath path that will be removed from \a path when adding to archive Examples should make it more clear what is the path added to the zip. Below function will also adds empty directories if you have them.
I've made some changes to code given by Mark Byers. If you have python3.5+, and specifically want to zip up a Python package, use zipapp: $ python -m zipapp myapp
(Note that you can't run subpackages as the entry point from a zipped archive.) Zipping a Python app: If you're trying to zip up a python package with a _init_.py and _main_.py, and you don't want the parent dir, it's $ python -m zipfile -c zipname sourcedir/* Zipping up Python (or just don't want parent dir): zip if you want it, it won't do it automatically) and sourcedir is the path to the directory. Where zipname is the name of the destination file you want (add. You can do this with Python from the shell also using the zipfile module: $ python -m zipfile -c zipname sourcedir I did have an issue testing this on Cygwin with 2.7 - it wants a root_dir argument, for cwd: make_archive('zipfile_name', 'zip', root_dir='.') If base_dir is farther down from root_dir it will exclude files not in the base_dir, but still archive the files in the parent dirs up to the root_dir. Here the zipped archive will be named zipfile_name.zip. Root_dir=None, # root for archive - current working dir if Noneīase_dir=None) # start archiving from here - cwd if None too 'zip', # the archive format - or tar, bztar, gztar In Python 2.7+, shutil has a make_archive function. How can I create a zip archive of a directory structure in Python? In a Python script
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